It is clear that the factor e i p would always contribute a value of 1 to the winding number. If we want to exclude the straight flushes, we need to subtract 4*2^10 from the 8^10 term since there are 2 cards of each rank in each of the 4 suits. To obtain explicitly the relation between the winding number and the parameters of the system t 0, t 1, and t 2, we factor h ext 1 ( p) in the following way: (31) h ext 1 ( p) e i p ( t 2 e i p + t 1 + t 0 e i p). If you really have an odd number of children in the class, one of your students will not have a partner, leaving someone as the 'odd man out. I think it is easiest for the kids to understand what an odd number is FIRST by lining them up by twos. So the probability of a natural straight (or straight flush) is:ģ,221,225,472/38,722,819,230,810 =~ 1 in 12,021 Here are five easy ways to teach odd and even numbers 1. The number of combinations that exist from the deck of 108 cards:Ĭ(108,10) = 108!/98!/10! = 38,722,819,230,810 OBJECTIVE OF PHASE 10: Complete all ten phases first NUMBER OF PLAYERS: 2-6 Players MATERIALS: Phase 10 deck (110 cards) TYPE OF GAME: Rummy AUDIENCE: 13+. For each rank there are 8 possible cards so this leads to 8^10 = 1,073,741,824 combinations for any given rank sequence. The math with wilds would be a lot more difficult.įor a natural 10-card straight, we have 3 rank sequences possible: 1-10, 2-11, and 3-12.

Correct me if I'm wrong, but I'm assuming you got dealt a natural 10 card straight.

Odd numbers phase 10